upload with curl

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Today I played a little bit with Curl (again)

while I have a compleet upload class sometimes I need simple upload functions in custum CMS apps.

This time I have to import a CSV file into a database and I wnat to upload the and remove the file afterwards.
So I thought this must be easy with Curl, but id doesn't like this: All examples are about uploading to a remote server but is this remote also the server where the script is running? It doesn't look like...

finally I found a snippet that match a little bit like waht I need:

Code:

<?php
$postData = array();
$postData[ 'file_name' ] = "@test.txt";
$postData[ 'submit' ] = "UPLOAD"; // don't know why this is here
      
$ch = curl_init();

curl_setopt($ch, CURLOPT_URL, $url ); // what is the $url its where the script is executed   
curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
curl_setopt($ch, CURLOPT_POST, 1 );

curl_setopt($ch, CURLOPT_POSTFIELDS, $postData );

$response = curl_exec( $ch ); 

At the end should $response holding the content of the text file, but it doesn't...

By the way this could be a good example to store uploaded data into a database...

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You should replace the $url here :

curl_setopt($ch, CURLOPT_URL, $url );

with the actual url that you are sending the post data.

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You should replace the $url here :

curl_setopt($ch, CURLOPT_URL, $url );

with the actual url that you are sending the post data.

I post the data to the same script (PHP_SELF)

so I need add there an url like: http://www.mydomain.com/myuploadform.php ?

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Yes and it will post the data to that url.

Have in mind that the keys to the $postData array are the keys in the $_POST array when you retrieve the data.

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... but the file is not inside the post array

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The @ sign indicates that it will upload the file (like in a multipart form)

You should check the $_FILES array for the file.

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The @ sign indicates that it will upload the file (like in a multipart form)

You should check the $_FILES array for the file.

I will give it try (have to write some bills first)

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same result like before

This is my code:

Code:

<?php
if (isset($_POST['Submit'])) {
$postData = array();
$postData['upload'] = "@".$_FILES['upload']['name'];
$postData['Submit'] = $_POST['Submit'];

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, "http://".$_SERVER['HTTP_HOST'].$_SERVER['PHP_SELF']); 
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $postData);
if (!$response = curl_exec($ch)) {
echo curl_error($ch);
}
curl_close($ch);
print_r($response);
}
?>

and this is my form:

Code:

<form name="form1" enctype="multipart/form-data" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
  <div>
    <label for="upload">Select a file...</label>
<input type="file" name="upload" size="30">
    <input type="submit" name="Submit" value="Submit">
  </div>
</form>

the result is this error: "failed creating formpost data"

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Try to send a file without using the $_FILES array at the beginning, to see if it works.

eg. $postData['upload'] = "@myfile.txt";

then in the url that you post type something like:

var_dump ( $_FILES );

Is it working that way?

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changed the code into:

Code:

<?php
if (isset($_POST['Submit'])) {
$postData = array();
$postData['upload'] = "@robots.txt";
$postData['Submit'] = $_POST['Submit'];

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, var_dump ( $_FILES )); 
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $postData);
if (!$response = curl_exec($ch)) {
echo curl_error($ch);
}
curl_close($ch);
print_r($response);
}
?>

and this is the result:


array(1) {
  ["upload"]=>
  array(5) {
    ["name"]=>
    string(18) "joomla contest.txt"
    ["type"]=>
    string(10) "text/plain"
    ["tmp_name"]=>
    string(25) "E:\WINDOWS\TEMP\php21.tmp"
    ["error"]=>
    int(0)
    ["size"]=>
    int(1469)
  }
}
<url> malformed

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So it works right

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I accepted to get the content from the uploaded file like in this script:

Code:

<?php
if (!empty($_FILES['userfile']['name'])) {
$fileName = $_FILES['userfile']['name'];
$tmpName  = $_FILES['userfile']['tmp_name'];
$fileSize = $_FILES['userfile']['size'];
$fileType = $_FILES['userfile']['type'];
$fp = fopen($tmpName, "r");
$content = fread($fp, filesize($tmpName));
fclose($fp);
}

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I tried a little bit more but it seems to me not working, CURL is great but tje information at net is not very big...

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Wait a sec. What version of php you have?

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Wait a sec. What version of php you have?

ver 5.1x

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That's ok.

Then propably you missunderstood something.

Did you manage to upload a hardcoded file? (eg. "@myfile.txt")

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That's ok.

Then propably you missunderstood something.

Did you manage to upload a hardcoded file? (eg. "@myfile.txt")

why? I want to use curl to do that...

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Because maybe the problem is in the way that you get the file that the user submits.

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do I missed something, I thought I use curl to upload a file via a form...

actually its should be a replacement for the php code I posted before...

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Curl is to post data in general.

You should have 3 pages.

1) A form that user submits a file

2) A page that get that information, and post it to the third page

3) A page that parses the $_POST and the $_FILES arrays

My guess is that the problem is on the page #2

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