return http_code with cURL

Just a simple function to return the http code (404, 200, 301 etc.)

Code:

<?php
function get_link_header($aUrl) {
if (preg_match("/^http:\/\//",$aUrl)) {
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $aUrl);
curl_setopt($ch, CURLOPT_HEADER, 1);
curl_setopt($ch, CURLOPT_NOBODY, 1);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_TIMEOUT, 30);
curl_exec($ch);
$info = curl_getinfo($ch);
curl_close ($ch);
if (!empty($info)) {
return $info['http_code'];
} else {
return 0;
}
} else {
return 0;
}
}

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Nice snippet.

BTW I think that this directive :

curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);

is not needed. Feel free to post that to the codex library

Nice snippet.

BTW I think that this directive :

curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);

yes, this is need otherwise the whole deaher is returned (I thought the same)

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lol

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