Dynamic (2 level) navigation list

I'm new to php mysql but found this tutorial http://www.tutorialized.com/tutorial/Dynamic-2-level-navigation-list/21070 and would ask if there is somewhere I could see what it looks like, please?

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you got my mail (Welcome at webdigity)

I'm trying to figure out how to make dynamic menus and have found this http://www.projectseven.com/tutorials/navigation/auto_hide/index.htm and then use it here on my testsite http://www.tinemuller.dk/wholocations/bookcode/ . When I figure out how to make this functioning I think I will be using this http://www.projectseven.com/products/menusystems/pmm/index.htm .
 
Do you have some files for download to the tutorial? I couldn't find them. I downloaded another tutorial http://www.tutorialized.com/view/tutorial/Dynamic-Dropdown-Menu/15808 which had source code.

If some of you use this tutorial on a site could I then see it in action, please?

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the complete code is used in the tutorial and I send you the link to the live example by mail (http://www.step2.nl/producten.php ).

actually the HTML code from the "Pop Menu Magic" should be the same but has much more (ajax?) code to get this smooth effect.

having a drop down menu is a case for CSS/javascript

I saw your site http://www.step2.nl/producten.php thanks but you don't use it dynamic, right?

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I saw your site http://www.step2.nl/producten.php thanks but you don't use it dynamic, right?

you mean this JS effect?

Sorry for don't understand this tutorial but I have tried reading the tutorial http://www.tutorialized.com/tutorial/Dynamic-2-level-navigation-list/21070 and made the table as told to but can't figure out how to use it. There must be missing some text or code I think for this to work?

There is NOT mentioned a database only a table and where to put all the code and what should this file be called? I just copied all the code and pasted it in a index.php file but then what to do?

Have you made this tutorial Olaf?

The tutorial mentions it is 'powered by PHP and MySQL' MySQL = database, and the table would be the database table that is used to store the menu items in.

the

Code:

CREATE TABLE `dyn_menu` (
  `id` INT(11) NOT NULL AUTO_INCREMENT,
  `label` VARCHAR(50) NOT NULL DEFAULT '',
  `link_url` VARCHAR(100) NOT NULL DEFAULT '#',
  `parent_id` INT(11) NOT NULL DEFAULT '0',
  PRIMARY KEY  (`id`)
) TYPE=MyISAM;

part is the MySQL command to create the database table.

Am I the only person who doesn't understand this tutorial? Please tell me a little more about how to use this, please?

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Am I the only person who doesn't understand this tutorial? Please tell me a little more about how to use this, please?

maybe you need some basic php skills?

start with setting up the database (use phpmyadmin) and come back if you have this done (don't forget to enter some records)

I have got some help from a danish forum and my testsite can now be seen here http://www.tinemuller.dk/2level_tutorial/ but he say that I need a connections to mysql but as being a beginner and not told in the tutorial it's not so easy, sorry.:-(

It could also be told a little more clear how and what to write in the database for it to work.

I think you should write this two things in the tutorial so other beginners don't have to waste so much time as I had.

Now I have to figure out how to make the connection?

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I have got some help from a danish forum and my testsite can now be seen here http://www.tinemuller.dk/2level_tutorial/ but he say that I need a connections to mysql but as being a beginner and not told in the tutorial it's not so easy, sorry.:-(

It could also be told a little more clear how and what to write in the database for it to work.

I think you should write this two things in the tutorial so other beginners don't have to waste so much time as I had.

Now I have to figure out how to make the connection?

do you checked the PHP manual? (never said that this tutorial is for beginners )

or try to search the net for some php/mysql beginner tutorial

After setting up your database and creating your table you should know how to connect to it, this is very basic stuff and not part of many tutorials. Here's one way of connecting:

Code:

<?php
// database connection details
$db_host = "localhost"; // hostname of your MySQL server. You most likely don't have to change this
$db_name = "yourDBname"; // database name
$db_user = "yourDBusername"; // database user
$db_pass = "yourDBpassword"; // database password

// Lets open up a connection to the database
$db = mysql_connect($db_host,$db_user,$db_pass);
mysql_select_db ($db_name) or die ("Cannot connect to database");

Now it connect http://www.tinemuller.dk/2level_tutorial/index.php .

This is was I got now with the help from the danish forum. Can you help me with some informations what to put in the database?

-- Struktur-dump for tabellen `dyn_menu`
--

CREATE TABLE `dyn_menu` (
  `id` int(11) NOT NULL auto_increment,
  `label` varchar(50) collate latin1_general_ci NOT NULL default '',
  `link_url` varchar(100) collate latin1_general_ci NOT NULL default '#',
  `parent_id` int(11) NOT NULL default '0',
  PRIMARY KEY  (`id`)
) ENGINE=MyISAM  DEFAULT CHARSET=latin1 COLLATE=latin1_general_ci AUTO_INCREMENT=2 ;

--
-- Data dump for tabellen `dyn_menu`
--

INSERT INTO `dyn_menu` (`id`, `label`, `link_url`, `parent_id`) VALUES
(1, 'Forside', 'index.php', 0);

INSERT INTO `dyn_menu` (`id`, `label`, `link_url`, `parent_id`) VALUES
(2, 'subitem', 'index.php', 1);

will insert a sub-menu-item

INSERT INTO `dyn_menu` (`id`, `label`, `link_url`, `parent_id`) VALUES
(3, 'second', 'index.php', 0);

will create a second main item

you will have to replace the index.php in both records of course to point to the correct pages (which will also have to include the menu)

I try to use the same script and keep hanging on this browser error:

Code:

Warning: Invalid argument supplied for foreach() in /home/eendit/domains/2cv-onderdelen.nl/public_html/includes/testmenu.php on line 24

that part of the script is here:

Code:

include "../connect.php";
include "../config.php";
include "functies.php";



// nieuw menu begin
$sql = "SELECT id, label, link_url, parent_id FROM dyn_menu ORDER BY parent_id, id ASC";
$items = mysql_query($sql);
while ($obj = mysql_fetch_object($items)) {
    if ($obj->parent_id == 0) {
        $parent_menu[$obj->id]['label'] = $obj->label;
        $parent_menu[$obj->id]['link'] = $obj->link_url;
    } else {
        $sub_menu[$obj->id]['parent'] = $obj->parent_id;
        $sub_menu[$obj->id]['label'] = $obj->label;
        $sub_menu[$obj->id]['link'] = $obj->link_url;
        $parent_menu[$obj->parent_id]['count']++;
    }
}
mysql_free_result($items);

// here starts line number 23
foreach ($parent_array as $pkey => $pval)
{
    if (!empty($pval['count'])) {
        $menu .= "  <li><a class=\"".$extra_style."\" href=\"".$pval['link']."?".$qs_val."=".$pkey."\">".$pval['label']."</a></li>\n";
    } else {
        $menu .= "  <li><a href=\"".$pval['link']."\">".$pval['label']."</a></li>\n";
    }
}

    if (!empty($_REQUEST[$qs_val])) {
    $menu .= "<ul id=\"".$sub_id."\">\n";
    foreach ($sub_array as $sval) {
        if ($pkey == $_REQUEST[$qs_val] && $pkey == $sval['parent']) {
            $menu .= "<li><a href=\"".rebuild_link($sval['link'], $qs_val, $sval['parent'])."\">".$sval['label']."</a></li>\n";
        }
    }
    $menu .= "</ul>\n";
    }

echo dyn_menu($parent_menu, $sub_menu, "menu", "nav", "subnav");

Can someone please tell what I can do to resolve this error?

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check if your sql is valid, next check if both arrays have values

Thanks Olaf, problem is fixed

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