If a variable has been unset with unset(), it will no
longer be set. isset() will
return FALSE if testing a variable that has been set to NULL. Also
note that a NULL byte ("\0") is not equivalent to
the PHP NULL constant.
Warning: isset() only works with variables as passing anything
else will result in a parse error. For checking if
constants are set use the
defined() function.
<?php
$var = '';
// This will evaluate to TRUE so the text will be printed. if (isset($var)) { echo "This var is set so I will print."; }
// In the next examples we'll use var_dump to output // the return value of isset().
// The key 'hello' equals NULL so is considered unset // If you want to check for NULL key values then try: var_dump(array_key_exists('hello', $a)); // TRUE
?>
Note: Because this is a
language construct and not a function, it cannot be called using
variable functions